In this section we will show how one can generalize the proof of existence
of the Dirichlet problem on the unit disk, given by Theorem 2
in Section 3, to the case in which we have, as the boundary
condition, non-integrable real functions
defined on
boundaries given by non-differentiable curves
on the plane. We
will be able to do this if the non-integrable real functions, despite
being non-integrable over the whole curves
, are locally integrable
almost everywhere on those curves, and if, in addition to this, the
non-integrable hard singularities involved have finite degrees of
hardness. The definition of the concept of local integrability almost
everywhere is that given by Definition 4, in
Section 7. The additional difficulty that appears in this case
is the same which was discussed in Section 6, due to the fact
that the curve
is not differentiable at the finite set of points
, for
. Just as in that case, this will
require that we impose one additional limitation on the real functions
giving the boundary conditions, namely that any integrable hard
singularities where they diverge to infinity do not coincide with any of
the points
.
The proof will follow the general lines of the one given for integrable
real functions in Section 6, with the difference that, just as
we did in Section 7, instead of showing that the corresponding
functions on the unit circle
are integrable there,
we will show that they are locally integrable almost everywhere there. In
addition to this, instead of using the existence theorem for integrable
real function on the unit circle, which was given by Theorem 1
in Section 2, we will use the corresponding result for
non-integrable real functions which are locally integrable almost
everywhere on the unit circle, which was given by Theorem 2 in
Section 3. Since that result depends also on the non-integrable
hard singularities of the real functions having finite degrees of
hardness, we will also show that the hypothesis that the functions
have this property implies that the corresponding
functions
have the same property as well. In order to do
this we will use once again the technique of piecewise integration which
was introduced in [#!CAoRFIV!#].
The preliminary result given by Lemma 3 in Section 7
is still valid here. As a consequence of this we may conclude at once
that, under the conditions that we have here, the hypothesis that
is locally integrable almost everywhere on
, with
the exclusion of the finite set of points
, for
, implies that
is locally integrable
almost everywhere on the unit circle
, with the exclusion of the
corresponding finite set of points
.
We must now discuss the issue of the degrees of hardness of the
non-integrable hard singularities of the function on
. Since by hypothesis
has non-integrable hard
singularities at the points
, it clearly follows that
also has hard singularities at the corresponding points
, which may be non-integrable ones. In order to discuss their
degrees of hardness we will use the technique of piecewise integration,
that is, we will consider sectional integrals of
on closed
intervals contained within a neighborhood of the point
where it
has a single isolated hard singularity. Let us show the following
preliminary fact about a real function
defined from a real
function
which is locally integrable almost everywhere on
, and which has non-integrable hard singularities at the finite set
of points
.
Since the real functions must diverge to infinity at non-integrable hard
singular points, the fact that has an isolated hard
singularity on
is immediate. Since these singularities are all
isolated from each other, and since they do not coincide with the points
where
is non-differentiable, there is on
a
neighborhood of the point
within which
is differentiable
and there are no other non-integrable hard singularities of
. Since the conformal mapping is continuous, it follows
that there is on
a neighborhood of the corresponding point
within which there are no zeros of the derivative of
and no other hard singularities of
. The
construction of the two sectional primitives of
by means
of piecewise integration is the same as the one which was executed before
for Lemma 4 in Section 7, resulting in
Equation (44). After we change variables from
to
on the two sectional integrals in that equation we get
where all the symbols involved are the same as before. Since the
derivative
which appears in these integrals is finite,
and therefore limited, everywhere within the two lateral intervals
involved, due to the fact that the inverse conformal transformation
is analytic and therefore differentiable within
these intervals, it follows that there are two pairs of real numbers
and
, as well as
and
, such that
![]() |
everywhere within each interval. Note that, since the conformal
transformation, besides being continuous and differentiable, is also
invertible within each interval, the derivatives above cannot change sign
and thus cannot be zero. Therefore, the pair of bounds and
may be chosen to have the same sign, and so may the pair
of bounds
and
. By exchanging the derivative
by these extreme values we can obtain upper and lower bounds for the
sectional integrals, and therefore we get for the sectional primitives in
Equation (53),
![]() |
We now recognize the integrals that appear in these expressions as the
sectional primitives of the function
, so that we get
![]() |
These expressions are true so long as
and
, as well as the corresponding quantities
and
on
, are not zero, but
since the singularities at
are non-integrable hard ones, we
cannot take the limit in which these quantities tend to zero. Note that,
since
and
have the same sign, and also
and
have the same sign, if the sectional
primitives of the function
diverge to infinity in this
limit, then so do the sectional primitives of the function
. Therefore, we may conclude that the hard singularity of
is also a non-integrable one. Since we may take further
sectional integrals of these expressions, without affecting the
inequalities, it is immediately apparent that, after a total of
successive piecewise integrations, we get for the
sectional
primitives
![]() |
Since the non-integrable hard singularity of
at the point
which corresponds to
has a finite degree of
hardness, according to the definition of the degrees of hardness, which
was given in [#!CAoRFI!#] and discussed in detail for the case of real
functions in [#!CAoRFIV!#], there is a value of
such that the limit
in which
and
can be
taken for the sectional primitives
and
, thus implying that the
piecewise primitive
of
is an
integrable real function on the whole interval
, with a borderline hard
singularity, with degree of hardness zero, at the point
. It
follows from the inequalities, therefore, that the corresponding limit in
which
and
can
be taken for the functions
and
, thus implying that the
piecewise primitive
of
is also
an integrable real function on the whole interval
, with a borderline hard
singularity, with degree of hardness zero, at
. Therefore, the
non-integrable hard singularity of
at
has a
finite degree of hardness, to wit the same degree of hardness
of the
corresponding non-integrable hard singularity of
at
. This establishes Lemma 5.
We have therefore established that, under the hypothesis that the hard
singularities where
diverges to infinity do not coincide
with any of the points
where
is non-differentiable, so
long as
is locally integrable almost everywhere on
, and so long as its non-integrable hard singularities have finite
degrees of hardness, these same two facts are true for
on
. Since we thus see that the necessary properties of the real
functions are preserved by the conformal transformation, we are therefore
in a position to use the result of Theorem 2 in
Section 3 in order to extend the existence theorem of the
Dirichlet problem to non-integrable real functions which are, however,
integrable almost everywhere on
, this time for the case of
non-differentiable curves.
In this section, using one more time the results from the previous sections, we will establish the following theorem.
Similarly to what was done in the three previous sections, the proof
consists of using the conformal transformation between the closed unit
disk and the union of the curve with its interior, which according to
the analysis in Section 4 always exists, to map the given
boundary condition on
onto a corresponding boundary condition on the
unit circle, then using the proof of existence established before by
Theorem 2 in Section 3 for the closed unit disk to
establish the existence of the solution of the corresponding Dirichlet
problem on that disk, and finally using once more the conformal
transformation to map the resulting solution back to
and its interior,
thus obtaining the solution of the original Dirichlet problem. The list of
conditions on the real functions is now the following.
The rest of the proof is identical to that of the three previous cases.
Therefore, once again we may conclude that, due to the existence theorem
of the Dirichlet problem on the unit disk of the plane , which in
this case was established in by Theorem 2 Section 3,
we know that there is an inner analytic function
such that
its real part
is harmonic within the open unit disk
and satisfies
almost everywhere at the
boundary
. Just as before, we get on the
plane the complex
function
which is analytic in the interior of the curve
. Therefore, the real part
of
is
harmonic and thus satisfies
![]() |
(50) |
in the interior of , while we also have that
![]() |
(51) |
almost everywhere on . This establishes the existence, by
construction, of the solution of the Dirichlet problem on the
plane, under our current hypotheses. This completes the proof of
Theorem 6.
In this way we have generalized the proof of existence of the Dirichlet problem from the unit circle to all simple closed curves with finite total lengths on the plane, that can be either differentiable or non-differentiable on a finite set of points, but now for boundary conditions given by non-integrable real functions which are locally integrable almost everywhere and have at most a finite set of hard singular points.