In this section we will show how one can generalize the proof of existence
of the Dirichlet problem on the unit disk, given by Theorem 2
in Section 3, to the case in which we have, as the boundary
condition, non-integrable real functions
defined on
boundaries given by differentiable curves
on the plane. We will be
able to do this if the non-integrable real functions, despite being
non-integrable over the whole curves
, are however locally
integrable almost everywhere on those curves, and if, in addition to this,
the non-integrable hard singularities of the inner analytic functions
involved have finite degrees of hardness. The definition of the concept of
local integrability almost everywhere is similar to that given for the
unit circle by Definition 2, in Section 3. In our case
here the precise definition of local integrability almost everywhere is as
follows.
The proof will follow the general lines of the one given for integrable
real functions in Section 5, with the difference that, since the
real functions
are assumed to be non-integrable on
, but locally integrable almost everywhere there, instead of
showing that the corresponding functions
on the unit
circle
are integrable there, we will show that they are locally
integrable almost everywhere there. In addition to this, instead of using
the result for integrable real function on the unit circle, which was
given by Theorem 1 in Section 2, we will use the
corresponding result for non-integrable real functions which are locally
integrable almost everywhere on the unit circle, which was given by
Theorem 2 in Section 3. Since that result depends
also on the non-integrable hard singularities of the real functions having
finite degrees of hardness, we will also show that the hypothesis that the
functions
have this property implies that the
corresponding functions
have the same property as well. In
order to do this we will use the technique of piecewise integration
which was introduced and employed in [#!CAoRFIV!#], where it played a
crucial role.
We will start by showing the following preliminary fact about a real
function defined from a real function
which is locally integrable almost everywhere on
, and which has
non-integrable hard singularities at the finite set of points
,
for
.
Since
is integrable on
we have that
![]() |
(37) |
exists and is finite. If we now consider the integral
![]() |
(38) |
and transform variables from to
, recalling that
, we get
The absolute value of the derivative shown exists and is finite on
, given that
![]() |
(40) |
where
is analytic on
and therefore
differentiable there. We also have that
is integrable on
. It follows that, since the integrand in the right-hand side of
Equation (39) is the product of a limited real function with
an integrable real function, and therefore is itself an integrable real
function, the integral in Equation (39) exists and is finite,
thus implying that
is integrable on the closed interval
. This establishes Lemma 3.
As an immediate consequence of this preliminary result, under the
conditions that we have here, the hypothesis that
is
locally integrable almost everywhere on
, with the exclusion of the
finite set of points
, implies that
is locally
integrable almost everywhere on
, with the exclusion of the
corresponding finite set of points
.
We must now discuss the issue of the degrees of hardness of the
non-integrable hard singularities of the function on
. Since by hypothesis
has non-integrable hard
singularities at the points
, it clearly follows that
also has hard singularities at the corresponding points
, which may be non-integrable ones. In order to discuss their
degrees of hardness we will use the technique of piecewise integration,
that is, we will consider sectional integrals of
on closed
intervals contained within a neighborhood of the point
where it
has a single isolated hard singularity. Let us show the following
preliminary fact about a real function
defined from a real
function
which is locally integrable almost everywhere on
, and which has non-integrable hard singularities with finite
degrees of hardness at the finite set of points
.
Since the real functions must diverge to infinity at non-integrable hard
singular points, the fact that has an isolated hard
singularity on
is immediate. Since these singularities are all
isolated from each other, there is on
a neighborhood of the point
within which there are no other non-integrable hard
singularities of
. Since the conformal mapping is
continuous, it follows that there is on
a neighborhood of the
corresponding point
within which there are no other hard
singularities of
. Given that the point
corresponds to the angle
, let the closed interval
contain the point
and
be contained in this neighborhood, so that we have
![]() |
(41) |
where the sole hard singularity of which is contained
within this interval is the one at the point
. Let us now
consider a pair of closed intervals contained within this neighborhood,
one to the left and one to the right of the point
, so that we
have
![]() |
![]() |
![]() |
|
![]() |
![]() |
![]() |
(42) |
where
and
are two
sufficiently small positive real numbers, so that we also have
![]() |
![]() |
![]() |
|
![]() |
![]() |
![]() |
(43) |
Let us now consider sectional primitives of the real function
on these two intervals. Since the singularity of
at
may not be integrable, we cannot integrate
across the singularity, but we may integrate within these two lateral
closed intervals, thus defining two sectional primitives of
, one to the left and another one to the right of
,
where
is the notation for a primitive of
with respect to
, where
and
are two arbitrary reference points, one within each
of the two lateral closed intervals, and where we have
![]() |
If we change variables from to
on the two sectional
integrals in Equation (44), we get
where
and
are the reference
points on
corresponding respectively to
and
. Since the derivative
which
appears in these integrals is finite everywhere on
, and therefore
limited, due to the fact that the inverse conformal transformation
is analytic and hence differentiable on the curve
, it follows that there are two real numbers
and
such that
![]() |
(46) |
everywhere on . Note that, since the conformal transformation,
besides being continuous and differentiable, is also invertible on
, the derivative above cannot change sign and thus cannot be zero.
Therefore, the two bounds
and
may be chose to have the
same sign. By exchanging the derivative by these extreme values we can
obtain upper and lower bounds for the sectional integrals, and therefore
we get for the sectional primitives in Equation (46),
![]() |
We now recognize the integrals that appear in these expressions as the
sectional primitives of the function
, so that we get
![]() |
These expressions are true so long as
and
, as well as the corresponding quantities
and
on
, are not zero, but
since the singularities at
are non-integrable hard ones, we
cannot take the limit in which these quantities tend to zero. Note that,
since
and
have the same sign, if the sectional primitives
of the function
diverge to infinity in this limit, then
so do the sectional primitives of the function
. Therefore,
we may conclude that the hard singularity of
is also a
non-integrable one. Since we may take further sectional integrals of these
expressions, without affecting the inequalities, it is immediately
apparent that, after a total of
successive piecewise integrations, we
get for the
sectional primitives
![]() |
Since the non-integrable hard singularity of
at the point
which corresponds to
has a finite degree of
hardness, according to the definition of the degrees of hardness, which
was given in [#!CAoRFI!#] and discussed in detail for the case of real
functions in [#!CAoRFIV!#], there is a value of
such that the limit
in which
and
can be
taken for the sectional primitives
and
, thus implying that the
piecewise primitive
of
is an
integrable real function on the whole interval
that corresponds to
, with a borderline hard
singularity, with degree of hardness zero, at the point
. It
follows from the inequalities, therefore, that the corresponding limit in
which
and
can
be taken for the functions
and
, thus implying that the
piecewise primitive
of
is also
an integrable real function on the whole interval
, with a borderline hard
singularity, with degree of hardness zero, at
. Therefore, the
non-integrable hard singularity of
at
has a
finite degree of hardness, to wit the same degree of hardness
of the
corresponding non-integrable hard singularity of
at
. This establishes Lemma 4.
We have therefore established that, so long as
is locally
integrable almost everywhere on
, and so long as its non-integrable
hard singularities have finite degrees of hardness, these same two facts
are true for
on
. Since we thus see that the
necessary properties of the real functions are preserved by the conformal
transformation, we are therefore in a position to use the result of
Theorem 2 in Section 3 in order to extend the
existence theorem of the Dirichlet problem to non-integrable real
functions which are, however, integrable almost everywhere on
,
still for the case of differentiable curves.
In this section, using once again the results from the previous sections, we will establish the following theorem.
Similarly to what was done in the two previous cases, in
Sections 5 and 6, the proof consists of using the
conformal transformation between the closed unit disk and the union of the
curve with its interior, which according to the analysis in
Section 4 always exists, to map the given boundary condition on
onto a corresponding boundary condition on the unit circle, then using
the proof of existence established before by Theorem 2 in
Section 3 for the closed unit disk to establish the existence of
the solution of the corresponding Dirichlet problem on that disk, and
finally using once more the conformal transformation to map the resulting
solution back to
and its interior, thus obtaining the solution of the
original Dirichlet problem. The list of conditions on the real functions
is now the following.
The rest of the proof is identical to that of the two previous cases, in
Sections 5 and 6. Therefore, once again we may
conclude that, due to the existence theorem of the Dirichlet problem on
the unit disk of the plane , which in this case was established by
Theorem 2 in Section 3, we know that there is an
inner analytic function
such that its real part
is harmonic within the open unit disk and satisfies
almost everywhere at the boundary
. Just as before, we get on the
plane the complex function
which is analytic in the interior of the curve
. Therefore, the real part
of
is
harmonic and thus satisfies
![]() |
(47) |
in the interior of , while we also have that
![]() |
(48) |
almost everywhere on . This establishes the existence, by
construction, of the solution of the Dirichlet problem on the
plane, under our current hypotheses. This completes the proof of
Theorem 5.
In this way we have generalized the proof of existence of the Dirichlet problem from the unit circle to all differentiable simple closed curves with finite total lengths on the plane, for boundary conditions given by non-integrable real functions which are locally integrable almost everywhere and have at most a finite set of hard singular points.