As we will see in the subsequent sections, it is possible to extend the
proof of existence of the Dirichlet problem to boundaries other than the
unit circle, through the use of conformal transformations. Therefore, as a
preliminary to the proof of further versions of the existence theorem, in
this section we will describe such conformal transformations and examine
some of their well-known properties, targeting their use here. In order to
do this, consider two complex variables and
and the
corresponding complex planes, a complex analytic function
defined on the complex plane
with values on the complex plane
, and its inverse function, which is a complex analytic function
defined on the complex plane
with values on the
complex plane
,
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(10) |
Consider a bounded and simply connected open region on the complex
plane
and its image
under
, which is a similar
region on the complex plane
. It can be shown that if
is analytic on
, is invertible there, and its derivative has no
zeros there, then its inverse function
has these same
three properties on
, and the mapping between the two complex
planes established by
and
is conformal, in
the sense that it preserves the angles between oriented curves at points
where they cross each other. Note that this mapping is a bijection between
the two regions, and establishes an equivalence relation that can be
extended in a transitive way to other regions.
Consider now that the regions under consideration are the interiors of
simple closed curves. One of these curves will be the unit circle
on the complex plane
, and the other will be a given curve
on the complex plane
. We will assume that the curve
has
finite total length, for two reasons, one being to ensure that the
interior of the curve is a bounded set, and the other being to ensure that
the integrals of real functions over the curve
are integrals over
a finite-length, compact domain. Since
, being analytic, is
in particular a continuous function, the image on the
plane of the
unit circle
on the
plane must be a continuous closed curve
. We can also see that
must be a simple curve, because the
fact that
is invertible on
means that it cannot
have the same value at two different points of
, and therefore no
two points of
can be the same. Consequently, the curve
cannot self-intersect.
We thus see that, so far, we are restricted to simple closed curves
with finite total lengths. However, there are further limitations
on the curves, implied by our hypotheses. Since the transformation is
conformal and thus preserves angles, it follows that in this case the
smooth unit circle
is mapped onto another equally differentiable
circuit
. One can see this by considering the angles between
tangents to the curve
at pairs of neighboring points, the
corresponding elements on the curve
, and the limit of these angles
when the two points tend to each other, given that the transformation is
conformal. Therefore, with such limitations one cannot map the unit circle
onto a square or any other polygon. This limitation can be lifted by
allowing the derivative of
to have a finite number of
isolated zeros on the curve
, which then implies that the
derivative of
will have a finite number of
corresponding isolated singular points on
.
Let us assume that the unit circle is described by the real
arc-length parameter
on the
plane, and that the curve
is described by a corresponding real parameter
on the
plane. Let us assume also that
is chosen in such a way
that
over the curve
, just as
over
, which means that
is also an
arc-length parameter. Since every point
on the curve
is
mapped by the conformal transformation onto a corresponding point
on the curve
, and since a point
on
is described by
a certain value of
, while the corresponding point
on
is described by a certain value of
, it is clear that the
complex conformal transformation induces a corresponding real
transformation between the values of
and the values of
,
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(11) |
where the real function is continuous, differentiable and
invertible on
. We will refer to the function
as the
real transformation induced on the curve
by the complex conformal
transformation
. The same is true for the inverse
transformation, which induces the inverse function of
, on the
curve
,
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(12) |
where the real function
is continuous and invertible
on
, and also differentiable so long as
is a differentiable
curve. Before we proceed, we must now consider in more detail the question
of what is the set of curves
for which the structure described
above can be set up. We assume that this curve is a simple closed curve of
finite total length, and the question is whether or not this structure can
be set up for an arbitrary such curve. Given the curve
, the only
additional objects we need in order to do this is the conformal mapping
and its inverse
, between that curve
and the unit circle
.
The existence of these transformation functions can be ensured as a
consequence of the famous Riemann mapping theorem, and of the associated
results relating to conformal mappings between regions of the complex
plane. According to that theorem, a conformal transformation such as the
one we described here exists between any bounded simply connected open set
of the plane and the open unit disk. In addition to this, one can show
that this conformal mapping can be extended to the respective boundaries
as a continuous function so long as the boundary curve satisfies a
certain condition [#!RMPQiu!#].
The condition on that implies the existence of the continuous
extension to the boundary is that every point on that curve be what is
called in the relevant literature a simple point. This means that no
point of
can be a multiple point, which in essence is a
point on the boundary that is accessible from the interior via two or more
independent continuous paths contained in the interior, that cannot be
continuously deformed into each other without crossing the boundary. We
can see, therefore, that this condition has a topological character. Note
that the presence of a multiple point on the boundary means that, even if
the open set under consideration is simply connected, its closure
will not be. Therefore, one way to formulate this condition is to
simply state that the closure of the bounded simply connected open set
must also be simply connected.
Since the existence of a multiple point at the boundary means that this
boundary is not a simple curve, it follows that, under the limitations
over that we have here, the conformal mapping on the open unit
disk can always be continuously extended to the unit circle, and hence
from the interior of the curve
to that curve, which is mapped from
the unit circle. Therefore, we conclude that it is a known fact that such
a conformal transformation exists for all possible simple closed curves
with finite total lengths, and in particular for all such curves
which are also differentiable, in which case the extension is also
differentiable on the unit circle
. It is therefore not necessary
to impose explicitly any additional hypotheses about the existence of the
conformal transformation, regardless of whether or not the curves
under consideration are differentiable.
Let us close this section with a discussion of the nature of the
singularities that appear in the case of simple closed curves
which are not differentiable at a finite set of points
, for
. The additional difficulty that appears in this case
stems from the fact that, if the curve
is not differentiable at
the points
, then the derivative of the transformation
has isolated zeros at the corresponding points
on the curve
, and therefore the derivative of the inverse
transformation
has isolated hard singularities at
the points
. In order to see how this comes about we start by
noting that, since we have that
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(13) |
for all on the closed unit disk, differentiating this equation we
get, due to the chain rule,
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(14) |
Therefore, to every point on
where the derivative of the
transformation has a zero corresponds a point
on
where
the derivative of the inverse transformation diverges to infinity. Taking
absolute values we have, in terms of the arc-length parameters
and
,
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(15) |
which implies that
In fact, the real function in the left-hand side of this last equation has
a removable singularity at every point where the first derivative in the
product diverges and the second one is zero. Consequently, they can be
removed by simply redefining the product by continuity at these points.
When we approach one of the points , which are characterized by
the values
of the parameter
, along the curve
, we have that
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(17) |
where the corresponding points are characterized by the values
of the parameter
, along the curve
.
Although the derivative
does, therefore, have hard
singularities at
, we can show that these are still integrable
singularities. We simply integrate the expressions in either side of
Equation (16) absolutely over
, thus obtaining
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(18) |
If we now change variables in this integral from to
, we
get the integral over
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(19) |
This shows that the real function appearing as the integrand in this
integral is an integrable real function on . Therefore the hard
singularities where the derivative
diverges to infinity
are integrable hard singularities, which therefore have degree of hardness
zero. These are also referred to as borderline hard singularities. Note
that, as a consequence, the corresponding singularities of the inverse
real transformation
itself must be soft ones, with
degrees of softness equal to one.